Question 983040
The ratio of Jack to Chris's money was 12 : 5 at first.
 After Jack saved another $340 and Chris saved another $174, Jack had twice of Chris.
 How much did Jack have in the end ?
:
Let x = the multiplier
then
12x = Jacks original amt
5x = Chris's amt
:
{{{((12x+340))/((5x+174))}}} = 2 (Jack has twice as much as Chris)
12x + 340 = 2(5x + 174)
12x + 340 = 10x + 348
12x - 10x = 348 - 340
2x = 8
x = 4 is the multiplier
:
then
12*4 = $48 Jack's amt originally
48 + 340 = $388 Jack amt in the end