Question 983092
h(x) = ln(cos(x^2))
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It's the "chain rule."
--> 1/(cos(x^2))  1st term
times -sin(x^2)  2nd term
times 2x  3rd term
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= {{{-2x*sin(x^2)/(cos(x^2))}}}
= {{{-2x*tan(x^2)}}}