Question 82369
{{{5^(x-2)=3^(2(3-x)) }}}
{{{5^(x-2)=3^(6-2x)}}}
take the Log of both sides and divide , log by log , and x by x
{{{(x-2)log5=(6-2x)log3}}}

so {{{(x-2)/(6-2x) }}} = {{{log3/log5 }}}
now using the calculator, solve normally
{{{(x-2)/(6-2x) }}} = 0.68
(0.68)(6-2x) = (x-2)
4.09-1.36x=x-2
x=6.09/2.36
x=2.58