Question 983029
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n_1\sin\theta_1\ =\ n_2\sin\theta_2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin\theta_2\ =\ \frac{n_1}{n_2}\sin\theta_1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \theta_2\ =\ \arcsin\left(\frac{n_1}{n_2}\sin\theta_1\right)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \