Question 983024
.
{{{x^2+(5/6)x=0}}}
Take 1/2 of the co-efficient of x:
{{{(1/2)(5/6)=5/12}}} (Remember this)
Square it:
{{{(5/12)^2=25/144}}}
Add to both sides of the original equation:
{{{x^2+(5/6)x+(25/144)=(25/144)}}}
Using the number you remembered above, write the left side as a square:
{{{(x+5/12)^2=25/144}}} The sign is the parenthesis is the same as the sign of the co-efficient of x in the original equation (+(5/6)x so the sign is +)