Question 982997
<font face="Times New Roman" size="+2">


Let *[tex \Large r_c] represent the speed of the current.  The net speed downstream is then *[tex \Large 8\ +\ r_c] and the net speed upstream is *[tex \Large 8\ -\ r_c].  Let *[tex \Large t] represent the time it takes to row  upstream, then *[tex \Large 16\ -\ t] is the time it takes to row downstream.  Since distance equals rate times time:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (8\ -\ r_c)t\ =\ 39]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (8\ +\ r_c)(16\ -\ t)\ =\ 39]


Solve the 2X2 system for *[tex \Large r_c] and *[tex \Large t]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \