Question 982998
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(f\circ g\right)(x)\ =\ f\left(g(x)\right)\ =\ 3\left(g(x)\right)^2\ -\ 1\ =\ 3\left(2x\ +\ 5\right)^2\ -\ 1\ =\ 3\left(4x^2\ +\ 20x\ +25\right)\ -\ 1\ =\ 12x^2\ +\ 60x\ +\ 75\ -\ 1]


To find *[tex \Large f\left(g(-4)\right)], just substitute -4 in place of *[tex \Large x] and do the arithmetic.


The other problem works the same way.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \