Question 982998
f(x) = 3x^2 - 1



f(x) = 3(x)^2 - 1



f(g(x)) = 3(g(x))^2 - 1 ... replace every x with g(x)



f(g(x)) = 3(2x + 5)^2 - 1 ... replace the g(x) on the right side with 2x+5



f(g(-4)) = 3(2(-4) + 5)^2 - 1 ... replace every x with -4. Now evaluate



f(g(-4)) = 3(-8 + 5)^2 - 1



f(g(-4)) = 3(-3)^2 - 1



f(g(-4)) = 3(9) - 1



f(g(-4)) = 27 - 1



f(g(-4)) = 26



I'll let you do the other part.