Question 982910
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Both ways are correct.  If you start counting at n = 1, then for a(1) to equal 6, you have to have 6 + (1 - 1)*624 and for a(1) to equal 2 for the geometric series, you have to have 2 * 3^(1-1).


But if you start your count at n = 0, the arithmetic series first term is 6 + 624*0 = 6, and the geometric is 2*3^0 = 2.


In the first case, 1 to 8 is 8 terms.  In the second case, 0 to 7 is 8 terms.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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