Question 982878
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a.  The probability that the first marble is not purple times the probability the second marble is not purple given that the first marble is not purple times the probability that the third marble is not purple given that the first and second marbles are not purple times the probability the fourth marble is not purple given that the first, second, and third marbles are not purple.  If *[tex \Large p] is the number of non-purple marbles, and *[tex \Large n] is the total number of marbles, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{p(p-1)(p-2)(p-3)}{n(n-1)(n-2)(n-3)}]


b.  Zero.  There is no chance of selecting a button of any color from a bag of marbles.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \