Question 982696
{{{3^t}}} is larger than {{{2^t}}} when {{{t > 0}}}


So {{{1+3^t}}} is larger than {{{1+2^t}}} when {{{t > 0}}}


Ultimately, {{{1/(1+3^t)}}} is smaller than {{{1/(1+2^t)}}} when {{{t > 0}}}. The reciprocals make the relationship swap.
Eg: 6 > 5 so 1/6 < 1/5 (since 0.167 < 0.2)


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Note: if {{{t < 0}}}, then everything flips. So if they say "t is an integer" then there isn't enough info. If they said "t is a POSITIVE integer" then that's enough info to figure out that col A is larger.