Question 982834
Solve 4^(2x) = 7^(x-1).
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2x*log(4) = (x-1)*log(7) = x*log(7) - log(7)
2x*log(4) - x*log(7) = - log(7)
x*log(16) - x*log(7) = - log(7)
{{{x*(log(7) - log(16)) = log(7)}}}
x*log(7/16) = log(7)
{{{x = log(7)/log(7/16)}}}