Question 982712
Upper branch of a horizontal parabola, concave to the right.  Translated from reference position by 9 units to the left and 4 units downward.  The reference function equation would be {{{y=2*sqrt(x)}}}.  You will find that instead of this vertex at origin, your given equation has vertex moved to (-9,-4).



{{{graph(300,300,-10,2,-5,7,2*sqrt(x+9)-4)}}}


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The question was, or assigned task was to graph USING THE INTERCEPTS.
Let each variable be 0, one at a time, and solve for the other variable.


If y is 0,
{{{2sqrt(x+9)-4=0}}}
{{{2sqrt(x+9)=4}}}
{{{sqrt(x+9)=2}}}
{{{(sqrt(x+9))^2=4}}}
{{{x+9=4}}}
{{{x=4-9}}}
{{{x=-5}}}
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<b>Then this is the intercept  (-5,0)</b>.  This is seen on the graph, also can be helpful in making the graph.


If x is zero,
{{{y=2sqrt(0+9)-4}}}
{{{y=2*3-4}}}
{{{y=6-4=2}}}
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<b>The y intercept,  (0,2)</b>.