Question 982724
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The 7th term of the expansion of *[tex \Large (a\ +\ b)^9] is *[tex \Large {{9}\choose{6}}a^3b^6] or *[tex \Large 84a^3b^6].  Just substitute *[tex \Large 5x^3] for *[tex \Large a] and *[tex \Large \left(-\frac{1}{x}\right)] for *[tex \Large b] and then simplify.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \