Question 982713
to solve the following equation for {{{x}}}, make it equal to zero

{{{(a/x) - (b/(cx+d))=0}}}

when {{{a = 14}}}, {{{b = 3}}}, {{{c = 8}}} and {{{d = 5}}}, we have


{{{(14/x) - (3/(8x+5))=0}}}


{{{14(8x+5)/x(8x+5) - 3x/x(8x+5))=0}}}


{{{(112x+70)/x(8x+5) - 3x/x(8x+5))=0}}}


{{{(112x+70 - 3x)/x(8x+5))=0}}}


{{{(109x+70)/x(8x+5))=0}}}

numerator cannot be equal to zero, so 

{{{109x+70=0}}}...solve for {{{x}}}


{{{109x=-70}}}

{{{x=-70/109}}}

{{{x=-0.6422018348623853}}}

{{{x=-0.64}}}