Question 982608
Velocity is the derivative of distance with respect to time.
{{{s=k*sqrt(t)}}}
{{{v=ds/dt=k*(1/2)t^(-1/2)}}}
Acceleration is the derivative of velocity with respect to time.
{{{a=dv/dt=-(k/4)*t^(-3/2)}}}
So then velocity is inversely proportional to the square root of time and acceleration is inversely proportional to the cube of the square root of time.
Acceleration varies as the cube of the velocity.