Question 982555
I'm assuming you want the magnitude and direction of the resultant force since you already have the magnitude and direction of the individual forces.
In the x direction,
{{{F[x]=150cos(40)+100cos(170)=114.91-98.48=16.43}}}
{{{F[y]=150sin(40)+100sin(170)=96.42+17.36=113.78}}}
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{{{abs(F)=sqrt(F[x]^2+F[y]^2)=sqrt(16.43^2+113.78^2)=114.96}}}{{{lbs}}}
{{{theta=tan^(-1)(113.78/16.43)=81.78}}}{{{degrees}}}