Question 982597
{{{sqrt(((xLessThanNegThree)-2)^2)}}}, the binomial will be a negative number but then still inside the square root function, the binomial is being squared and becomes positive.


Also, understand that  {{{abs(x-2)=sqrt((x-2)^2)}}}, and the critical x value is 2.  Negative 3 clearly makes  {{{x-2<0}}}.


{{{abs(x-2)}}} when {{{x-2}}} is negative becomes  {{{abs(x-2)=-(x-2)=highlight(-x+2)}}}.



The second equation to analyze will work similarly.  x+2 will be negative for {{{x<-3}}}.