Question 982559
5% rate each compounding period.
1+0.05=1.05 rate or factor for 1 period which is 6 months.


p, initial invested
n, count of compounding periods  (which is a six month time)
{{{y=p(1.05)^n}}}


{{{1*1.05^n=2}}}, doubling the investment;
find logarithm of each side...


{{{log(10,(1.05)^n)=log(10,2)}}}
{{{n*log(10,1.05)=log(10,2)}}}
{{{highlight(n=log(10,2)/log(10,1.05))}}}


and then  {{{n(1/2)}}}  YEARS