Question 981333
{{{A[n]=sqrt(n)-sqrt(n+1)}}}
{{{A[1]=sqrt(1)-sqrt(2)=1-sqrt(2)}}}
{{{A[2]=sqrt(2)-sqrt(3)}}}
{{{A[3]=sqrt(3)-sqrt(4)=sqrt(3)-2}}}
{{{A[4]=sqrt(4)-sqrt(5)=2-sqrt(5)}}}
.
.
.
{{{S[1]=1-sqrt(2)}}}
{{{S[2]=1-sqrt(2)+sqrt(2)-sqrt(3)=1-sqrt(3)}}}
{{{S[3]=1-sqrt(3)+sqrt(3)-2=1-2=-1}}}
{{{S[4]=-1+2-sqrt(5)=1-sqrt(5)}}}