Question 982473
The perimeter of this triangle is 168 cm. The length of the longest side is twice that of the shortest side. The sum of the lengths of the shortest side and the longest side is 48 cm more than the length of side b. Find the length of each side.


The perimeter of this triangle is 168 cm.

a+b+c=168


 The length of the longest side is twice that of the shortest side. 
a=2c

The sum of the lengths of the shortest side and the longest side is 48 cm more than the length of side b.
a+c =b+48

a+b+c=168
substitute a+c

2b+48+=168

2b=120

b=60

a+b+c=168

a=2c

2c+60+c=168

3c=108
c= 36

a=2c

a= 72

72, 60,36