Question 982472


You need to solve an equation 


{{{2^(x+3)}}} = {{{3^x}}}.


Rewrite it as


{{{2^3}}}.{{{2^x}}} = {{{3^x}}},


{{{8}}} = {{{3^x/2^x}}},


{{{(3/2)^x}}} = {{{8}}}. 


Hence, 


{{{x}}} = {{{log(3/2, 8)}}}.



You can consider it as the final answer,  or you can rewrite it further


{{{x}}} = {{{1/log(8, (3/2))}}} = {{{1/(log(8,3) - log(8,2))}}} = {{{1/(log(8,3) - 1/3)}}}.