Question 982418
Not sure "the bottom";


Understanding the base is 5,
{{{1/6(log((x))+log((y)))-2log((x+3))}}}


{{{1/6log((xy))-2log((x+3))}}}


{{{1/log(((xy)^6))-2log((x+3))}}}


{{{-log(((xy)^6))-log(((x+3)^2))}}}


{{{-1(log(((xy)^6))+log(((x+3)^2))))}}}


{{{(-1)log(((xy)^6*(x+3)^2))}}}


{{{-log(((xy)^6*(x+3)^2))}}}-------or could show in corresponding {{{1/log(((xy)^6*(x+3)^2))}}}