Question 982370
.
W=width; L=length=3W-5cm; A=area=112cm^2
.
{{{LW=A}}}
{{{(3W-5cm)(W)=112cm^2}}}
{{{3W^2-5Wcm=112cm^2}}}
{{{3W^2-5Wcm-112cm^2=0}}}
{{{(W-7)(3W+16)=0}}}
{{{W-7=0}}} {{{OR))) {{{3W+16=0}}}
{{{W=7}}} {{{OR}}} {{{3W=-16}}}
{{{W=7}}} {{{OR}}} {{{W=-(16/3)}}}
ANSWER 1: The width is 7 cm.
.
{{{L=3W-5cm}}}
{{{L=3(7cm)-5cm}}}
{{{L=21cm-5cm}}}
{{{L=16cm}}}
ANSWER 2: The length is 16 cm.
.
CHECK:
A=LW
112cm^2=(16cm)(7cm)
112cm^2=112cm^2