Question 982307
Adding matrices is just like adding numbers.
Your matrices have 1 row with 3 elements (numbers) on each row.
You work with the first number on the matrices to the left of the equal sign
to get the first number in the result matrix to the right of the equal sign,
-14-(-4-16) = -14-(-20) = -14+20 = 6 ,
but that was already done for you.
You would work with the last(third) number on the matrices to the left of the equal sign
to get the last number in the result matrix to the right of the equal sign,
18-(0-8) = 18-(0-(-8)) = 18-8 = 10 ,
but that was already done for you.
The same calculation with the middle number is
{{{-19-(1x-12) = 5}}}
We can try to solve that for {{{1x}}} ,
and then figure out what was meant by {{{1x}}}.
Normally you would say that {{{1x}}} means {{{1}}} times {{{x}}} ,
and you would write it as just {{{x}}} .
Another interpretation is that what was meant by {{{1x}}} was
a two digit number with {{{1}}} as the tens digit and {{{x}}} as the units digit.
{{{-19-(1x-12) = 5}}}
{{{-(1x-12) = 5+19}}}
{{{-1x+12 = 24}}}
{{{-1x = 24-12}}}
{{{-1x = 12}}}
{{{1x=-12}}}
Normally you would say that {{{1x}}} means {{{1}}} times {{{x}}} ,
and you would write it as just {{{x}}} .
Another interpretation is that what was meant by {{{1x}}} was
a two digit number with {{{1}}} as the tens digit and {{{x}}} as the units digit.
Neither interpretation works for any of the options given.
Maybe there was a typo in the problem as given to you.