Question 982270
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The probability of k successes in n trials where the probability of success (p) on any given trial is found by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(k;n,p)\ =\ {{n} \choose{k}}p^k(1-p)^{n-k}]


where *[tex \LARGE {{n} \choose{k}}] is the number of combinations of n things taken k at a time or *[tex \LARGE \frac{n!}{k!(n-k)!}]


The cumulative probability of at most k successes in n trials where the probability of success (p) on any given trial is found by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(\leq k;n,p)\ =\ \sum_{j=0}^k\,{{n} \choose{j}}p^j(1-p)^{n-j}]


The standard deviation of the binomial distribution is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sigma\ =\ \sqrt{np(1-p)}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \