Question 982302

if you mean this:

{{{4sqrt(x) - 3=x}}}, then

{{{4sqrt(x) =x+3}}}

{{{(4sqrt(x))^2 =(x+3)^2}}}

{{{16x =x^2+6x+9}}}

{{{0 =x^2-16x+6x+9}}}

{{{0 =x^2-10x+9}}}

{{{0 =x^2-x-9x+9}}}

{{{0 =(x^2-x)-(9x-9)}}}

{{{0 =x(x-1)-9(x-1)}}}

{{{0 =(x-9)(x-1)}}}

solutions:

if {{{0 =(x-9)}}}=>{{{x=9}}}
if {{{0 =(x-1)}}}=>{{{x=1}}}


but, if you mean this:

{{{4sqrt(x - 3)=x}}}, then

{{{(4sqrt(x - 3))^2=x^2}}}

{{{16(x - 3)=x^2}}}

{{{16x - 48=x^2}}}

{{{0=x^2-16x+48}}}

{{{0=x^2-4x-12x+48}}}

{{{0=(x^2-4x)-(12x-48)}}}

{{{0=x(x-4)-12(x-4)}}}

{{{0 = (x-12)(x-4)}}}

solutions:

if {{{0 = (x-12)}}}=>{{{x=12}}}
if {{{0 = (x-4)}}}=>{{{x=4}}}