Question 982281


10*(cos(35°)+ i*sin(35°))/(5*(cos(100°) + i*sin(100°))) =   (a quotient has the modulus equal to the ratio of modulus and the argument equal to the difference of the arguments)


= {{{10/5}}}.(cos(35°-100°)+ i*sin(35°-100°) = 2*(cos(-65°) + i*sin(-65°)) =   (now replace the angle  -65°  by the angle between  0°  and  360°,  which is  360° - 65° = 295°)


= 2*(cos(295°) + i*sin(295°)).