Question 982294
2+log(2,X)=log(2,(3+X^2))


{{{2+log(2,X)=log(2,(3+X^2))}}}


{{{log(2,(3+X^2))-log(2,X)=2}}}


{{{log(2,((X^2+3)/X))=2}}}


This means  {{{2^2=(X^2+3)/X}}}------solve from here.


....
ultimately  {{{(X-1)(X-3)=0}}};
X is either 1 or 3.


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Assumed you have only one single variable, X
(not x).
Pick your case level and stay with it unless you have two separate variables, x and X, and that {{{x<>X}}}.