Question 982262
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{{{H=Height}}}; {{{W=Width=H+2m}}}; {{{D=diagonal}}}={{{sqrt(6)m}}}
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The height and width are two legs of a right triangle with diagonal as hypotenuse.
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{{{H^2+W^2=D^2}}} Substitute for W.
{{{H^2+(H+2m)^2=(sqrt(6)m)^2}}}
{{{H^2+H^2+4Hm+4m^2=6m^2}}}
{{{2H^2+4Hm-2m^2=0}}}*[invoke quadratic "H", 2, 4, -2 ]
H=0.4142 meters (approx)