Question 982192
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{{{x=2+sqrt(3)}}}
{{{x^2=4+2sqrt(3)+2sqrt(3)+3}}}
{{{x^2=7+4sqrt(3)}}}
{{{x^4=(x^2)^2=(7+4sqrt(3))^2=49+28sqrt(2)+28sqrt(3)+48}}}
{{{x^4=97+56sqrt(3)}}}
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Using same method:
{{{y^4=97-56sqrt(3)}}}
So:
{{{X^4+y^4=97+56sqrt(3)+97-56sqrt(3)}}}={{{194}}}