Question 982085
the  side of the outer most square is 8

area = 64

the side of the first inner square = {{{sqrt(4^2+4^2)}}}

={{{4*sqrt(2)}}}

Area of first inner square = 32

Every inner square is half in area of the outer square

6 squares
54,32,16,8,4,2

Add them up 116 in^2