Question 83822
There are two ways. 1 1/3 is actually 1 + 1/3, so you'd have
{{{8^(1+(1/3))}}}
Use the rule {{{x^(a+b) = (x^a)(x^b)}}}
{{{8^(1+(1/3)) = (8^1)(8^(1/3))}}}
The cube root of 8 is 2
{{{8^(1+(1/3)) = 8*2}}}
{{{8*2 = 16}}} answer
The other way is 1 1/3 = 4/3
{{{8^(1+(1/3)) = 8^(4/3)}}}
Note that 4/3 is actually {{{4*(1/3)}}}
Use the rule {{{x^(a*b) = (x^a)^b}}}
{{{8^(4/3) = (8^(1/3))^4}}}
{{{8^(4/3) = 2^4}}}
{{{8^(4/3) = 16}}} same answer