Question 83827
Solve using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
It would help if you were to put your equation into the standard form for quadratic equations:{{{ax^2+bx+c = 0}}}
{{{x^2 = -7x+12}}} Add 7x to both sides.
{{{x^2+7x = 12}}} Now subtract 12 from both sides.
{{{x^2+7x-12 = 0}}} So now you can see that a = 1, b = 7 and c = -12.
Applying the quadratic formula, you get:
{{{x = (-7+-sqrt(7^2-4(1)(-12)))/2(1)}}} Simplify this.
{{{x = (-7+-sqrt(49-(-48)))/2}}}
{{{x = (-7+-sqrt(97))/2}}}
The solutions are:
{{{x = (1/2)(-7+sqrt(97))}}} and {{{x = (1/2)(-7-sqrt(97))}}}