Question 982075
That description makes the equation need to be  {{{4/(x+1)-3/(x+2)=1}}}.  The properly placed parentheses are necessary.


Multiply the left side and the right side by  (x+1)(x+2), which is the simplest common denominator, and simplify.


{{{4(x+2)-3(x+1)=(x+1)(x+2)}}}
{{{4x+8-3x-3=x^2+3x+2}}}
{{{x^2+3x+2-4x-8+3x+3=0}}}
{{{x^2+2x-3=0}}}
{{{(x-1)(x+3)=0}}}



Either {{{x=1}}}  Or {{{x=-3}}}.