Question 982009

distance is:
{{{d=21mil}}}
time:
from  {{{5:30am }}} to {{{7am}}} is {{{1.5h}}}

subtract the time she need for make up
{{{1.5h-48mi=1.5h-0.8h=0.7h}}}

so, to drive on set she has{{{ t=0.7h}}}

since {{{d=s*t}}}, we have

{{{s=d/t}}}.........substitute {{{21mil}}} for {{{d}}} and {{{0.7h}}} for {{{t}}}

{{{s=21mil/0.7h}}}

{{{s=210mil/7h}}}

{{{s=30(mil/h)}}}

so,  she must drive {{{30(mil/h)}}} to get on to work on time