Question 981966

Please use the remainder theorem to evaluate {{{4x^3 - 3x^2 + 2x - 3 when x=2}}}
<pre>Since {{{f(x) = 4x^3 - 3x^2 + 2x - 3}}}, then remainder when x = 2 is:
{{{f(2) = 4(2)^3 - 3(2)^2 + 2(2) - 3}}}
f(2) = 4(8) - 3(4) + 4 - 3
f(x) = 32 - 12 + 4 - 3
{{{highlight_green(f(x) = 21)}}} (Remainder)