Question 981943
Your equation shown is ambiguous.  One would only try guessing the base is meant to be 2.


{{{log((t))+log((t+1))=1}}}, with the base of 2.


{{{log((t(t+1)))=1}}}


{{{2^1=t(t+1)}}}


{{{t^2+t=2}}}


{{{t^2+t-2=0}}}


{{{(t-1)(t+2)=0}}}


2 to no power gives any negative value, so you can only accept t=1.