Question 981891
The equation is
h = -16t^2 +103t + 41
this is a parabola that opens downward
to find time t when the rocket hits the round solve the following for t
-16t^2 +103t + 41 = 0
use quadratic formula,
t = (-b + or - square root(b^2 - 4ac)) / 2a
we get the following solutions for t
t = 6.813586792 or t = −0.376086792
we want the positive value for t, therefore
the rocket will hit the ground in 6.8 seconds
here is the graph
{{{ graph( 300, 200, -6, 10, -600, 200, -16x^2 +103x + 41) }}}