Question 981804
{{{x^(-10) = 1/(x^(10))}}}


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As x gets closer to 0, the value of {{{1/(x^(10))}}} will get larger towards positive infinity. Plug in x = 0.1, x = 0.01, x = 0.001, etc to find that {{{1/(x^(10))}}} is getting larger.


So as x --> 0, y --> +infinity


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As x heads off to infinity, {{{1/(x^(10))}}} gets smaller and smaller. You follow the same idea from the previous part above, but the idea is reversed. So


x --> +infinity, y --> 0