Question 981717
Find the fifth roots of 243(cos 260° + i sin 260°).
260/5 = 52
360/5 = 72
--> 52 + n*72, n = 0,1,2,3,4
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= 3cis(52), 3cis(124), 3cis(196), 3cis(268), 3cis(340)