Question 981508
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Let *[tex \Large x] represent the tens digit and *[tex \Large y] represent the ones digit.  The value of the number is *[tex \Large 10x\ +\ y] and the sum of the digits is *[tex \Large x\ +\ y].  Further, the value of the number with the digits reversed is *[tex \Large 10y\ +\ x].


So we have:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  10x\ +\ y\ =\ 4(x\ +\ y)]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  10x\ +\ y\ +\ 27\ =\ 10y\ +\ x]


Solve the 2X2 system of equations for *[tex \Large x] and *[tex \Large y]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \