Question 981438

{{{(a^3-b^3)+(a^2+ab+b^2)}}}....since {{{(a^3-b^3)=(a-b) (a^2+a b+b^2)}}}, we have

{{{(a-b) (a^2+ab+b^2)+(a^2+ab+b^2)}}}

{{{((a-b) +1)(a^2+ab+b^2)}}}

{{{(a-b +1)(a^2+ab+b^2)}}}