Question 981376
Use Cramer's rule,
{{{A=(matrix(3,3,
1,-1,3,
2,1,2,
-2,-2,1))}}}
{{{abs(A)=5}}}
.
.
.
{{{A[x]=(matrix(3,3,
2,-1,3,
2,1,2,
3,-2,1))}}}
{{{abs(A[x])=-15}}}
.
.
.
{{{A[y]=(matrix(3,3,
1,2,3,
2,2,2,
-2,3,1))}}}
{{{abs(A[y])=14}}}
.
.
.
{{{A[z]=(matrix(3,3,
1,-1,2,
2,1,2,
-2,-2,3))}}}
{{{abs(A[z])=13}}}
.
.
.
{{{x=abs(A[x])/abs(A)=-15/5=-3}}}
.
.
{{{y=abs(A[y])/abs(A)=14/5}}}
.
.
{{{z=abs(A[z])/abs(A)=13/5}}}
.
.