Question 83662
I am not sure of how this problem was set-up.  If it is:
Y= {{{(x/1)+1)}}}
Than the answer is 
y=x+1
To graph refer to the slope-intecept form of a line:
y=any y-term
m=the slope of the line
x=the corresponding x-term
b=the y-intercept (the point where the line crosses the y-axis at (0,b))
.
y=mx+b
y=x+1
The slope is 1 and the y-intercept is +1 or point (0, 1)
Graphing:
{{{ graph( 300, 200, -6, 5, -10, 10, x+1) }}} 
.
If the set-up is
y={{{(x/(1+1))}}}
y={{{(x/2)}}}
y={{{(x/2+0)}}}
y={{{(1/2x+0)}}}
y={{{((1/2)x)}}}
Than the slope is 1/2 and the y-intercept is 0 or the point (0, 0)
Graphing:
{{{ graph( 300, 200, -6, 5, -10, 10, (1/2)x) }}}