Question 981317
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x=negative integer
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{{{(x)(2x-5)=x+56}}}
{{{2x^2-5x=x+56}}} Subtract (x+56) from each side.
{{{2x^2-6x-56=0}}} Divide each side by 2.
{{{x^2-3x-28}}}
{{{(x-7)(x+4)=0}}}
{{{x-7=0}}} {{{OR}}} {{{x+4=0}}}
{{{x=7}}} {{{OR}}} {{{x=-4}}}
Since we are looking for a negative integer,
ANSWER: The negative integer is -4.
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CHECK:
(x)(2x-5)=x+56
(-4)(2(-4)-5)=-4+56
(-4)(-8-5)=52
(-4)(-13)=52
52=52