Question 981295

{{{log((x +8)) = 1+ log((x -10))}}}

{{{log((x +8))-log((x -10)) = 1 }}}

{{{log((x +8)/(x -10)) = 1 }}}.....since {{{1}}} is {{{log(10,10)}}}, we have

{{{log((x +8)/(x -10)) = log((10)) }}}...if log same, then


{{{(x +8)/(x -10) = 10 }}}....solve for {{{x}}}

{{{(x +8) = 10(x -10) }}}

{{{x +8 = 10x -100 }}}

{{{100 +8 = 10x -x }}}

{{{108 = 9x }}}

{{{108/9 = x }}}

{{{x=12  }}}