Question 981190
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In order for the design to double in size, the circumference of the sphere must double in size.  The circumference is directly proportional to the radius, so if the circumference doubles, the radius must double.  The volume of a sphere is directly proportional to the <i>cube</i> of the radius.  So if you double the radius, the volume increases by *[tex \Large 2^3\ =\ 8] times.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \