Question 981197
This shows what the parts do:

{{{y=b^x}}}, basic exponential equation model;
{{{log(b,y)=x}}}, the logarithmic form.


Another way to understand:


{{{antilog=(base)^(logarithm)}}}



Exponential Form:  {{{2^x=3-t}}}
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{{{log(2,(3-t))=x}}}, just a change of the form.



Exponential Form:   {{{4^6t=(a+b)/a}}}------???
You must mean this:  {{{4^(6t)=(a+b)/a}}}
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{{{log(4,((a+b)/a))=6t}}}, changed to log form.



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Further comment:
A logarithm is an exponent.
The two equations  {{{log(b,y)=x}}} and {{{y=b^x}}}  are two equivalent equations.