Question 981156
Let x equal the first number
x + 2 equals the second number
The square of the second is (x + 2)^2
5 times the first number is 5(x)
(x + 2)^2 + 5(x) = 229
x^2 + 4x + 4 + 5x = 229
x^2 + 9x + 4 = 229
add -4 to each side
x^2 + 9x  = 225
add -225 to each side
x^2 + 9x - 225 = 0
It turns out that there is not an integer solution to the equation
so there is not a solution to the problem as stated.